burgerandcheese
Junior Member
- Joined
- Jul 2, 2018
- Messages
- 85
Q: Find the coordinates of each of the turning points of the curve y = x +√(8 - x²) and determine whether it is a maximum or minimum point.
I did dy/dx = 0 and I got x = ±2 , but x = -2 is extraneous so the curve only has a turning point at x = 2.
I graphed it on too: https://www.desmos.com/calculator/lgyw282qoq
However, when I checked on wolframalpha it said the curve has a global maximum at x = 2 and a global minimum at x = -2√2
https://www.wolframalpha.com/input/?i=y%3Dx%2Bsqrt(8-x%5E2)
how do I get x = -2√2 ?
I did dy/dx = 0 and I got x = ±2 , but x = -2 is extraneous so the curve only has a turning point at x = 2.
I graphed it on too: https://www.desmos.com/calculator/lgyw282qoq
However, when I checked on wolframalpha it said the curve has a global maximum at x = 2 and a global minimum at x = -2√2
https://www.wolframalpha.com/input/?i=y%3Dx%2Bsqrt(8-x%5E2)
how do I get x = -2√2 ?