Hi guys, first time here. Anyway I have this problem and I think I have a solution for it but I'm not sure I set up my original equation correct. Here is the problem:
A 16-lb turkey initially at 75 degrees is placed in an oven. After 75 minutes the turkey reaches 100 degrees. When will the turkey reach 160 degrees?
I am thinking that the rate at which the turkey cooks is directly proportional to the time its been in the oven, so I set up my equation as such: dy/dt = ky , with k being some constant.
So heres what I have done:
dy/dt = ky
1/y dy = k dt
integrate both sides to get ln|y| = kt + c1 (some constant)
y = e^(kt) * e^(c1)
y= B * e^(kt)
Using the intial conditions, I set the equation to 75 and solve for B first:
y(0) = 75 implies:
75 = B * e^(0*t)
75 = B * 1
B = 75
So then we can write the original equation as:
y = 75e^(kt)
Applying the next condition:
y(75) = 100
100 = 75e^(k * 75)
100/75 = e^(75k)
ln|100/75| = 75k
ln|100/75| / 75 = k
k = roughly .0051
So now we have the equation y = 75e^(.0051t)
And to find the answer to the question of when it will reach 160 degrees we set it equal to 160 as such:
160 = 75e^(.0051t)
160/75 = e^(.0051t)
ln|160/75| = .0051t
ln|160/75| / .0051 = t
t = about 148 minutes
That answer seems a bit off, so I am wondering if I set up my original equation wrong. Any suggestions, or am I just over thinking it?
A 16-lb turkey initially at 75 degrees is placed in an oven. After 75 minutes the turkey reaches 100 degrees. When will the turkey reach 160 degrees?
I am thinking that the rate at which the turkey cooks is directly proportional to the time its been in the oven, so I set up my equation as such: dy/dt = ky , with k being some constant.
So heres what I have done:
dy/dt = ky
1/y dy = k dt
integrate both sides to get ln|y| = kt + c1 (some constant)
y = e^(kt) * e^(c1)
y= B * e^(kt)
Using the intial conditions, I set the equation to 75 and solve for B first:
y(0) = 75 implies:
75 = B * e^(0*t)
75 = B * 1
B = 75
So then we can write the original equation as:
y = 75e^(kt)
Applying the next condition:
y(75) = 100
100 = 75e^(k * 75)
100/75 = e^(75k)
ln|100/75| = 75k
ln|100/75| / 75 = k
k = roughly .0051
So now we have the equation y = 75e^(.0051t)
And to find the answer to the question of when it will reach 160 degrees we set it equal to 160 as such:
160 = 75e^(.0051t)
160/75 = e^(.0051t)
ln|160/75| = .0051t
ln|160/75| / .0051 = t
t = about 148 minutes
That answer seems a bit off, so I am wondering if I set up my original equation wrong. Any suggestions, or am I just over thinking it?