Trying to solve for x^(1/2.2) = .2315

[trevor_kmd]

HAAAAALP

I thought that i could go about reducing this way:

log(x^(1/2.2) = .2315

log(x) * .4545 = .2315

log(x) = .2315/.4545

log(x) = .5093

But I'm radically incorrect as this results in ~3.23, and I know the result should be ~0.04.

 

[Deleted member 4993]

HAAAAALP

I thought that i could go about reducing this way:

log[x^(1/2.2)] = log(.2315)...... need to take log of both sides!

log(x) * .4545 = .2315

log(x) = .2315/.4545

log(x) = .5093

But I'm radically incorrect as this results in ~3.23, and I know the result should be ~0.04.

.