Trying to isolate the Y in this equation

[Dan McKinney]

X = b*(ACOSH(Y*c)/d)

I am trying to isolate the "Y" variable here. If this just involved simple math calculations, I could do it easily, but I don't know how to handle the inverse hyperbolic cosine function!

Can anyone help me? I need to get this to Y = ......

Thanks in advance!!

 

[MarkFL]

Hello, and welcome to FMH!

I would first write:

[MATH]\arcosh(Yc)=\frac{dX}{b}[/MATH]
And then:

[MATH]Yc=\cosh\left(\frac{dX}{b}\right)[/MATH]
And finally:

[MATH]Y=\frac{1}{c}\cosh\left(\frac{dX}{b}\right)[/MATH]

 

[Dan McKinney]

Mark - Thank you!! Makes sense!!

 

[pka]

X = b*(ACOSH(Y*c)/d) I am trying to isolate the "Y" variable here.

If were to try this, I would try the standard \(\displaystyle \cosh(t)=\dfrac{e^t-e^{-t}}{2}\).