Robertoxxx
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- Aug 28, 2017
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Hello guys, i need a bit of guidance with this problem;
In a truncated right cylinder, the top plane makes an angle of 45deg horizontal. and the shortest and longest elements are 27 and 5 units. Find the Volume.
Here's what a did so far, to find the diameter, i took out the triangle that can be formed from the top plane, with 27 and 5 as the longest/shortest units, i subtracted 27 and 5 to get the opposite side of the triangle which is 22 units.
Now that i have the angle formed in the triangle which is 45deg and 22 as the opposite side, i used the formula;
diameter = 22 / tan45, which gave me the value of 22, i then divided by 2 to get the radius which is 11.
then used the formula v=(pi)(11)^2 (27+5)/2 = 1936pi
But my professor told me that my answer was wrong, any help will be appreciated.
In a truncated right cylinder, the top plane makes an angle of 45deg horizontal. and the shortest and longest elements are 27 and 5 units. Find the Volume.
Here's what a did so far, to find the diameter, i took out the triangle that can be formed from the top plane, with 27 and 5 as the longest/shortest units, i subtracted 27 and 5 to get the opposite side of the triangle which is 22 units.
Now that i have the angle formed in the triangle which is 45deg and 22 as the opposite side, i used the formula;
diameter = 22 / tan45, which gave me the value of 22, i then divided by 2 to get the radius which is 11.
then used the formula v=(pi)(11)^2 (27+5)/2 = 1936pi
But my professor told me that my answer was wrong, any help will be appreciated.
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