Trouble with triangles

[RobertaN13]

hi there, im having a huge chapter test and I have no idea of how to solve it but I would appreciate some help...preferably solve the whole problem step by step.
Here goes :
In triangle ABC, sinA=0.7, sinB=0.35, side b=50. Find side a.

Thankz i really appreciate it :wink:

 

[soroban]

Hello, RobertaN13!

\(\displaystyle \text{In }\Delta ABC:\;\sin A\,=\,0.7,\;\sin B\,=\,0.35,\:\text{ side }b\,=\,50.\;\;\text{ Find side }a.\)

Your expected to know the Law of Sines: \(\displaystyle \L\:\frac{a}{\sin A}\:=\:\frac{b}{\sin B}\:=\:\frac{c}{\sin C}\)

We are given: \(\displaystyle \,\sin B\) and side \(\displaystyle b\).
We are given: \(\displaystyle \,sin A\) and we want side \(\displaystyle a\).

We'll use the first two fraction of the Law: \(\displaystyle \L\,\frac{a}{\sin A}\:=\:\frac{b}{\sin B}\)


Plug in what we know: \(\displaystyle \L\:\frac{a}{0.7}\:=\:\frac{50}{0.35}\;\;\Rightarrow\;\;a\:=\:\frac{(0.7)(50)}{0.35}\)

Therefore: \(\displaystyle \L\,a\:=\:100\)

 

[RobertaN13]

thank u so much I know the law of sines yet when faced with this kind of word problem I dont know how to start it off,...but once again thank you