Trisecting Angles

TJKoker

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Sep 11, 2006
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Hello good people,
My first time with you. Am I glad you're here. Spent 2 hours trying to figure this out for my son and came up zip, nada! Help!

angle 1 = 3x - 4y

angle 2 = x - y

angle 3 = y - 10

Find angle 3.

I solved for y, but I could not plug in the values and make it work. I'm going wrong somewhere.

Judging from the diagram, the sum of the 3 angles is just under 90 degrees. In the problem the angles had letter designations, but I don't know how to paste a drawing so I just simplified it.
 
angle 1 = 3x - 4y

angle 2 = x - y

angle 3 = y - 10

Find angle 3.

Sorry, TJ, but more info is needed on the relationships between the angles.
 
TJKoker said:
I solved for y, but I could not plug in the values and make it work. I'm going wrong somewhere.
Please provide the rest of the exercise, along with a clear listing of what you've done so far. For instance, your "subject" refers to trisecting angles. Is trisection involved somehow with these angles? What value did you get for "y"? And so forth.

Thank you.

Eliz.
 
TJKoker said:
angle 1 = 3x - 4y

angle 2 = x - y

angle 3 = y - 10

Find angle 3.

I solved for y, but I could not plug in the values and make it work. I'm going wrong somewhere.

Judging from the diagram, the sum of the 3 angles is just under 90 degrees. In the problem the angles had letter designations, but I don't know how to paste a drawing so I just simplified it.
Assuming angle 1 = angle 2 = angle 3

1--3x - 4y - x - y or 2x = 3y
2--x - y = y - 10 or 2y - x - 10
3--Multiply (2) by 2 or 4y - 2x = 20
4--Subtitute 2x = 3y into (3) or 4y - 3y = 20 making y == 20
5--Then, 60 = 2x or x = 30
6--Angle 1 = 3(30) - 4(20) = 10º
7--Angle 2 = 30 - 20 = 10º
8--Angle 3 = 20 - 10 = 10º
9--The trisected angle is therefore 30º making the trisected angles 10º each.
 
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