You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an alternative browser.
You should upgrade or use an alternative browser.
Trigonometry
- Thread starter Fritz
- Start date
D
Deleted member 4993
Guest
Are you allowed to use calculator?Hello I am Fritz, I new here. I was wondering if I can get some help with this trig. Exercise please...
If x=7.2°, find the value of sin(2x) and
5 tan x over 12...
Please show us what you have tried and exactly where you are stuck.
Please follow the rules of posting in this forum, as enunciated at:
https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520
Please share your work/thoughts about this assignment.
The first one you said "(5tanx)/ 12"Does 5 tan x over 12 mean "(5tanx)/12" or "5tan(x/12)"? BIG difference there.
D
Deleted member 4993
Guest
Are you allowed to use calculator?The first one you said "(5tanx)/ 12"
D
Deleted member 4993
Guest
so then use it!!Yes.
Your problem is:
, find the value of
sin(2*7.2º)
sin(14.4º)
Now tell us what did you get?
D
Deleted member 4993
Guest
It is that simple. Using the double angle formula:0.25 for both... But I don't think it's that simple... I think it has something to do with the formula: sin2x =2 sinx cosx
sin(2*7.2) = 2*sin(7.2) * cos(7.2) = 2* 0.12533 * 0.9921 =0.24869
exactly what you got by punching in
sin(14.4) =
in your calculator