kris.yarmak123
Junior Member
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- Jun 13, 2019
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The triangle PQR has Q = 43 degrees, p=20cm and q=15cm. The smallest value of P+R+r, correct to the nearest tenth is ____.
Please help me
Please help me
This is one of the two triangles possible, as I mentioned; and not the one they want. Good work so far; but don't stop here!So I got angle P = 65.4 degrees as the smallest value, angle R = 71.6 degrees and r=20.9.
So the answer is 96.2 right?For this case, r=8.4.
Now add up P+R+r for each case, pick the smallest, and you have the answer.
Well I added 65.4°+22.4°+8.4. I'm a little confusedHow did you get that? Please show the additions you did for each case.
There are two cases; you are mixing them together. It asked for "the smallest value of P+R+r", not the sum of the smallest value of each!Well I added 65.4°+22.4°+8.4. I'm a little confused
So I got angle P = 65.4 degrees as the smallest value, angle R = 71.6 degrees and r=20.9.
Add each triple of numbers separately.The other possibility for P is 114.6°. for R I guess it's 22.4°. and r = 20.9 or 8.4