Trigonometry Problem...please help!!!

Dwight

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Recall Snell's law, c1/c2=sin theta 1/sin theta 2, where c1 is the speed of light in one medium, c2 is the speed of light in a second medium, and theta1 and theta2 are the angles. Suppose a light is shining through the water into the air. As theta1 increases, theta2 approaches 90 degrees, at which point no light will emerge from the water. Assume the ratio c1/c2 in this case is .752. For what value of theta1 does theta2=90 degrees? This value is called the critical angle for water.[/i]

Please help, I have no idea where to start.
 
.752=sin(t<sub>1</sub>)/sin(t<sub>2</sub>)
If t<sub>2</sub> = 90° then sin(t<sub>2</sub>)=1 and
.752=sin(t<sub>1</sub>)
t<sub>1</sub> = sin<sup>-1</sup>(.752) = 48.8°
 
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