Trigonometry Help Please!

G'day,

One way:

Rewrite 2tanx as 2sinxcosx\displaystyle \frac{2\sin{x}}{\cos{x}}

Multiply through by cosx.

Rewrite cos2x\displaystyle \cos^2{x} as 1sin2x\displaystyle 1 - \sin^2{x}.

Solve the quadratic -you may find it easier to let sinx = t, and solve for t using the quadratic formula, then relate back to x.

Then get (cosx)^2 from there.
 
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