trigonometric ratios: why the tangent of a 45 angle is 1

minela22

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Nov 29, 2007
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Please help me solve this problem urgent!
Explain why the tangent of a 45 angle is 1
 
Re: trigonometric ratios

Do you know the identity:
tanx=sinxcosx\displaystyle tanx = \frac{sinx}{cosx} ?

If so, then what is sin45 and cos45 equal to?

If not, I'll prove it to you. Imagine a triangle ABC\displaystyle \triangle ABC with sides a, b, c, ACB\displaystyle \angle ACB is a right angle, and x=ABC\displaystyle x = \angle ABC
Code:
  A
   *
   **
   *  *
 b  *    *   c
   *      *
   *        *
   * * * * * * B
  C     a

From that, we have by definition:
sinx=bccosx=actanx=ba\displaystyle sinx = \frac{b}{c} \quad cosx = \frac{a}{c} \quad tanx = \frac{b}{a}

That means:
sinxcosx=bcac=bcca=bcac=ba=tanx\displaystyle \frac{sinx}{cosx} = \frac{\:\frac{b}{c}\:}{\:\frac{a}{c}\:} = \frac{b}{c} \cdot \frac{c}{a} = \frac{bc}{ac} = \frac{b}{a} = tanx

tanx=sinxcosx\displaystyle \therefore tanx = \frac{sinx}{cosx}
 
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