Trigonometric Proofs

Hello,
Thanks for your response, this is where im at, just trying to figure out how I can further manipulate the LHS so it equals the RHS.
Many thanks

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Here are some suggestions
sin2(x)tan(x)tan(x)+1=sin3(x)sin(x)+cos(x) & cos2(x)tan(x)+1=cos3(x)sin(x)+cos(x)\dfrac{\sin^2(x)\tan(x)}{\tan(x)+1}=\dfrac{\sin^3(x)}{\sin(x)+\cos(x)}~\&~\dfrac{\cos^2(x)}{\tan(x)+1}=\dfrac{\cos^3(x)}{\sin(x)+\cos(x)}
Can you factor sin3(x)cos3(x) ?\sin^3(x)-\cos^3(x)~? SEE HERE
 
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