Trigonometric equations / identities

[Vikash]

The equation tankx = -1/√3. Where k is a constant and k is greater than 0. Given that x = π/3 find a possible value for k. When I substitute the x value into the trig equation and solve it (taking tan inverse to both sides and then dividing by pi over 3) I get a negative answer...but they say k should be greater than 0. How am I to solve it?? HELP IS REALLY APPRECIATED THANKS!

 

[skeeter]

[MATH]\tan(u) = -\dfrac{1}{\sqrt{3}} \implies u = -\dfrac{\pi}{6} + n\pi \, , \, n \in \mathbb{Z}[/MATH]
[MATH]n = 1 \implies u = \dfrac{5\pi}{6}[/MATH]
[MATH]k \cdot \dfrac{\pi}{3} = \dfrac{5\pi}{6}[/MATH]
solve for k

 

[Vikash]

[MATH]\tan(u) = -\dfrac{1}{\sqrt{3}} \implies u = -\dfrac{\pi}{6} + n\pi \, , \, n \in \mathbb{Z}[/MATH]
[MATH]n = 1 \implies u = \dfrac{5\pi}{6}[/MATH]
[MATH]k \cdot \dfrac{\pi}{3} = \dfrac{5\pi}{6}[/MATH]
solve for k

Thanks??