Trigonometric Derivative: how to derive sec^2(x)

[Guest]

How do you derive sec^2(x)?

 

[ChaoticLlama]

Derive is not the same as differentiate.
Do not confuse the two terms.

y = sec²x

let u = secx
therefore: du/dx = secxtanx

y = u²

dy/dx = 2u * du/dx

dy/dx = 2(secx)secxtanx

dy/dx = 2sec²xtanx

 

[galactus]

:roll:

 

[pka]

Re: Trigonometric Derivatives

How do you derive sec^2(x)?

You have got to be ‘kidding’!
Your other questions are calculus III or above.
This one is freshman calculus at best!
What is your game? You cannot be that clueless, can you?