trig

[tsh44]

Hi how would I solve this problem?

sec x sinx =2 sinx

(answer must be between 0 and 2 pi)

thanks

 

[Daniel_Feldman]

sec x sinx =2 sinx


secxsinx-2sinx=0


sinx(secx-2)=0

sinx=0 and secx-2=0


Can you finish?

 

[tsh44]

Hi thanks I got 0 and pi for sin x=0 but how would you finish sec x=2?

 

[Unco]

sec = 1/cos

so sec(x) = 2 is the same as 1/cos(x) = 2

That is, cos(x) = 1/2

 

[tsh44]

Thank you Unco