trig: write 4sin pi/3 cos 5pi/6 as a sum

ShanikaC

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Apr 20, 2006
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how do you use the sum-to-product formula to write a product as a sum:


4sin pi/3 cos 5pi/6
 
sin(A)cos(B) = (1/2)sin(A+B) + (1/2)sin(A-B)

4sin(pi/3)cos(5pi/6) =

2sin(pi/3 + 5pi/6) + 2sin(pi/3 - 5pi/6) =

2sin(7pi/6) + 2sin(-pi/2) =

2(-1/2) + 2(-1) = -3
 
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