How do i reduce sqrt(3) - 1 / 1 + sqrt(3)? Thanks in advance, Sky :wink:
S skydog287 New member Joined Nov 6, 2005 Messages 1 Nov 6, 2005 #1 How do i reduce sqrt(3) - 1 / 1 + sqrt(3)? Thanks in advance, Sky :wink:
pka Elite Member Joined Jan 29, 2005 Messages 11,995 Nov 6, 2005 #3 1+3=3+1\displaystyle 1 + \sqrt 3 = \sqrt 3 + 11+3=3+1 (3−13+1)(3−13−1)=?\displaystyle \left( {\frac{{\sqrt 3 - 1}}{{\sqrt 3 + 1}}} \right)\left( {\frac{{\sqrt 3 - 1}}{{\sqrt 3 - 1}}} \right) = ?(3+13−1)(3−13−1)=?
1+3=3+1\displaystyle 1 + \sqrt 3 = \sqrt 3 + 11+3=3+1 (3−13+1)(3−13−1)=?\displaystyle \left( {\frac{{\sqrt 3 - 1}}{{\sqrt 3 + 1}}} \right)\left( {\frac{{\sqrt 3 - 1}}{{\sqrt 3 - 1}}} \right) = ?(3+13−1)(3−13−1)=?
