Trig Limit: 5 - 5cos^2 x / 8x^2

peblez

New member
Joined
Jan 29, 2007
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36
Can someone show me how to solve this limit

5 - 5cos^2 x / 8x^2

i'm not sure how to solve this

thanks
 
\(\displaystyle \L \frac{{5 - 5\cos ^2 (x)}}{{8x^2 }} = \left( {\frac{5}{8}} \right)\left( {\frac{{\sin (x)}}{x}} \right)^2\)
 
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