trig identities/substitution: square root of x^2+36 when x= 6tan(theta)

[killadza]

Use the trigonometric substitution to write the algebraic expression as a trigonometric function of θ, where 0 < θ < π/2.

square root of x^2+36 when x= 6tan(theta)

36sec^3(theta) is the closest i could get but i know its wrong. thanks for help, cheers

 

[Deleted member 4993]

Use the trigonometric substitution to write the algebraic expression as a trigonometric function of θ, where 0 < θ < π/2.

square root of x^2+36 when x= 6tan(theta)

36sec^3(theta) is the closest i could get but i know its wrong. thanks for help, cheers

How did you get that?

Can you please share your work?