trig help.

[jordan83]

Find all the solutions for 4cos(2@) - 2sqrt3 = 0

I am pretty sure you must add the 2sqrt2 to the other side and then divide both sides by 4.

Giving you cos(2@)=2sqrt3/4.

Now I am lost. haha. Help me please!!


sqrt= square root of
@= theta

 

[stapel]

Is it "sqrt(2)" or "sqrt(3)"? (You switch back and forth....)

Your methodology is correct, as far as it goes. But then you need to simplify, and use the basic reference-angle values you memorized (for 0°, 30°, 45°, 60°, and 90°) to figure out all the values that 2@ must be. Then divide through by 2 to find @.

Eliz.

 

[jordan83]

hey

I need help simplifying im terrible with fractions... then I can get it. Thanks!

 

[stapel]

Re: hey

I need help simplifying im terrible with fractions.

2/4 = 1/2

Eliz.