Trig Funtion Identity!

[needlutsofhlp]

ive been tryin to understand identity but i cant seem to get all the way through a problem my teacher just kind of expects everyone to know since a few kids in our clas actualy get the work.....any help will be greatly apriciated


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[stapel]

I'm sorry, but we cannot teach courses here.

Please post the full and exact text of the exercise with which you are having difficulty, the complete instructions, and a clear listing of all of the steps and reasoning you have tried thus far.

Thank you.

Eliz.

 

[needlutsofhlp]

...

this is one that i cant get though i keep tryin all the substitution that my teacher said i should do but truth is i dont know were to substitute it.

1/sin theta(1+sin theta) = 1+ 1/sin theta

i cant prove the equation...

 

[stapel]

i keep tryin all the substitution that my teacher said i should do

Which ones were those?

i dont know were to substitute it.

You would substitute into the given equation.

1/sin theta(1+sin theta) = 1+ 1/sin theta

I'm sorry, but your formatting is ambiguous. Do you mean the following?

. . . . .\(\displaystyle \large{\frac{1}{\sin{(\theta)}(1\,+\,\sin{(\theta)})} \,=\,1\,+\,\frac{1}{\sin{(\theta)}}}\)

If so, then the "identity" isn't true.

Eliz.

 

[needlutsofhlp]

...

well id ont knwo how to format it on here the way u do but no that not it the equation is


1/sin theta (1+sin theta)= 1 + 1/sin theta[/code]



the (1+sin theta) is beside the 1/sin theta not under

 

[Gene]

You seem to be saying it is the same as
(1+sin(theta))/sin(theta)=1+1/sin(theta)
If that is correct you don't need any thing but algebra.
(1+x)/x = 1+1/x