Trig Equations

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countrygal2242

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Given the following trig equation, please solve the equations below and show all steps involved to solving your given trig equation. Solve for the unknown variable on the interval, 0\le x\le 2\pi 0\le x\le 2\pi (0, Greater than/equal to, x, greater than or equal to, 2pi)

sin(2x)(sinx-1) = 0​
 
countrygal2242 said:
Given the following trig equation, please solve the equations below and show all steps involved to solving your given trig equation. Solve for the unknown variable on the interval, 0\le x\le 2\pi 0\le x\le 2\pi (0, Greater than/equal to, x, greater than or equal to, 2pi)

sin(2x)(sinx-1) = 0​
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If I were to this problem - I would start:

either sin(2x) = 0 → x =?

or sin(x) - 1 = 0 → x = ?

Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:

https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520

Please share your work/thoughts about this assignment.
 
Come on, you have a product that equals 0. It doesn't matter if you like or not like the looks of the factors, one or both of them must be 0.

sin(2x)(sin(x)-1) = sin(2x)*(sin(x)-1) = 0 so either sin(2x) = 0 or sin(x) - 1 =0.


In sin(x) - 1 = 0 you have a subtraction that equals 0. The only way the difference can be 0 is if the two terms you are subtracting are the same. So sin(x) = 1
 
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