show that \(\displaystyle sinh3\theta = 3sinh\theta + 4sinh^{3} \theta \)
am a bit stuck,,.....
\(\displaystyle sinh3\theta \) = \(\displaystyle sinh (2\theta + \theta) = sinh2\theta cosh\theta + cosh2\theta sinh\theta \)
am stuck from these line onwards, any help appreciated.
am a bit stuck,,.....
\(\displaystyle sinh3\theta \) = \(\displaystyle sinh (2\theta + \theta) = sinh2\theta cosh\theta + cosh2\theta sinh\theta \)
am stuck from these line onwards, any help appreciated.
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