Trig Chain Rule-done then simply

[shooterman]

. . . . . .$\displaystyle (x-2)^4(2x)+(x^2)(4(x-2)^3)$ This is the derivative I solved for.The book gives a answer I guess is simpled so.....

. . . . . .$\displaystyle 2x(x-2)^4+4x^2(x-2)^3$ Then I got stuck on how to make it look like the answer in the book which is...

. . . . . .$\displaystyle 2x(x-2)^3(3x-2)$

 

[galactus]

From your result, they just factored out $\displaystyle 2x(x-2)^{3}$

$\displaystyle 2x(x-2)^{3}((x-2)+2x)$

$\displaystyle 2x(x-2)^{3}(3x-2)$

 

[shooterman]

Awesome, can't believe i didn't notice that I feel Dumb. :lol: