Trig Chain Rule-done then simply

[shooterman]

. . . . . .\(\displaystyle (x-2)^4(2x)+(x^2)(4(x-2)^3)\) This is the derivative I solved for.The book gives a answer I guess is simpled so.....

. . . . . .\(\displaystyle 2x(x-2)^4+4x^2(x-2)^3\) Then I got stuck on how to make it look like the answer in the book which is...

. . . . . .\(\displaystyle 2x(x-2)^3(3x-2)\)

 

[galactus]

From your result, they just factored out \(\displaystyle 2x(x-2)^{3}\)

\(\displaystyle 2x(x-2)^{3}((x-2)+2x)\)

\(\displaystyle 2x(x-2)^{3}(3x-2)\)

 

[shooterman]

Awesome, can't believe i didn't notice that I feel Dumb. :lol: