amathproblemthatneedsolve
Junior Member
- Joined
- May 12, 2019
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- 189
This is usually called an Eulerian traceable graph It was proved in 1873 that a connected graph is traceable if and only if it has 0 or exactly two odd vertices. If it has to odd vertices the trace must begin at one and end at the other. This graph is such with vertices \(\displaystyle C~\&~F\)I believe the image below is traversable by a path: F>D>C>F>G>D>H>G>E>A>B>E>H>B>C Is this correct?
View attachment 14583
Also what's the reason for this being transverable if I may ask?
So this means I'm right If I read this properly!Now you are asking about the Travelling salesman problem.