Translating word prob to variation equation (gas volume)

[Gus]

At constant temperature the volume of a gas varies inversely as the pressure to which it is subjected. If the volume is 4470 cm^3 when the pressure is 487 kPa, determine the volume when the pressure is 7692 kPa.

can any body solve and explain?

Thanks

 

[stapel]

can any body solve and explain?

The short explanation: Variation equations translate as follows:

. . . . ."y varies directly as x": y = kx
. . . . ."y varies inversely as x": y = k/x
. . . . ."y varies with x and z": y = kxz

But if you missed the classes on variation equations, and the book and the class-notes you got from a friend aren't working, then a quickie explanation or one more worked example probably isn't going to help, either. :shock:

Instead, please try studying some of the many lessons available online:

. . . . .Google results for "variation equation inverse direct"

Once you have studied some lessons (at least two!) and have learned the basic terms and techniques, please attempt the exercise. If you get stuck, please reply showing all of your work and reasoning, starting with the basic form of the inverse-variation equation that you used. :idea:

Please be complete. Thank you!

Eliz.

 

[Gus]

Is this right? Or where did I go wrong?

At constant temperature the volume of a gas varies inversely as the pressure to which it is subjected. If the volume is 4470 cm^3 when the pressure is 487 kPa, determine the volume when the pressure is 7692 kPa.
v = k/p
k = v*p
k = (4470*cm^3*487)*kPa
k = 2176890*cm^3*kPa
v = 2176890*cm^3*kPa/(7692*kPa)

283*cm^3

 

[Deleted member 4993]

Re: Is this right? Or where did I go wrong?

At constant temperature the volume of a gas varies inversely as the pressure to which it is subjected. If the volume is 4470 cm^3 when the pressure is 487 kPa, determine the volume when the pressure is 7692 kPa.
v = k/p
k = v*p
k = (4470*cm^3*487)*kPa
k = 2176890*cm^3*kPa
v = 2176890*cm^3*kPa/(7692*kPa)........Looks good to me

283*cm^3