transforming quadratic relations

[Shoppingal]

Just want to make sure I am doing this right

Describe how to transform the graph of y =x^2 to produce the graph of each function

y=2(x-10)x^2+1

this is a vertical stretch of 2
horizontal shift 10 units to the right
vertical shift of 1 up

 

[Deleted member 4993]

Just want to make sure I am doing this right

Describe how to transform the graph of y =x^2 to produce the graph of each function

y=2(x-10)x^2+1

this is a vertical stretch of 2
horizontal shift 10 units to the right
vertical shift of 1 up

Correct

 

[soroban]

Hello, Shoppingal!

I assume you have a typo . . .

Just want to make sure I am doing this right

Describe how to transform the graph of \(\displaystyle y \,=\,x^2\)
. . to produce the graph of: .\(\displaystyle y\:=\:2(x-10)x^2+1\) . This is a cubic!

This is a vertical stretch of 2,
. . a horizontal shift 10 units to the right,
. . and a vertical shift of 1 up.

I'm sure you meant: .\(\displaystyle y \:=\:2(x-10)^2+1\)

 

[Deleted member 4993]

Hello, Shoppingal!

I assume you have a typo . . .


I'm sure you meant: .\(\displaystyle y \:=\:2(x-10)^2+1\)

Thanks Soroban - I glossed over it .... what was that you said second thing to go .... I seem to have lost the third thing now....