transformation of base functon

yfelix45

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Joined
Dec 20, 2011
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31
Hello,

I would like to know how would I explain the following question:

Describe the transformations you would have to apply to the base function y = sin x to graph the following:

y= sin(x - 60)

y = 2sinx

y = sin2x

y = -3sinx +1


I am confused by the explainations that were given the chapter and I don't know how to start to describe the transformations.

Your help is always appreciated

Thanks
yfelix45
 
y= sin(x - 60)
Shift the graph 'y=sinx' to left by 60.

y = 2sinx
Dilate the graph 'y=sinx' vertically by 2.

y = sin2x
Dilate the graph 'y=sinx' horizontally by 2.

y = -3sinx +1
Dilate the graph 'y=sinx' vertically by -3 then shift upwards by 1.
 
Thanks

hello freeman,

thanks for your help in explaining the question

yfelix45
 
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