transform h = a cos(bt + c) + d to model tide hts over 48-hr

reg

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I need to use the algebraic (transformation) method to develop a trigonometric model for data (tide heights over a 48hr period) of the form h= a cos (bt + c) + d and explain fully how i determined values of a, b, c, d.

i know it makes a periodic function if i plug that data into my graphics calculator but i just don't know what they mean by a trig model... or the algebraic method.. eek!

can anyone help me with what this is supposed to mean and where i should start?

thank you!!
:D
 
Re: Algebraic (transformation) and trigonometric model

reg said:
... i just don't know what they mean by a trig model ...

Hi reg:

A model that uses one of the trigonometry functions (eg: sin, cos, tan, sec, csc, cot) is a "trig model".

For example, if the electrical voltage of some circuit at time T is given by the expression

16000 * sin(T+0.5)

then we could say that this expression models the voltage at time T. Because this expression contains a trigonometry function, we could further say that it's a trig model.

Since they already gave you the form h = a * cos(b * t + c) + d

it's kinda redundant for them to instruct you to come up with a trig model. They've already done that for you by providing an expression for h that includes a trigonometry function (cosine).

reg said:
I need to use the algebraic (transformation) method ... i just don't know what they mean by ... the algebraic method.

Transformations have to do with the relationship between changes made to a function's DEFINITION and the resulting effects that those changes make in the function's GRAPH.

For example, you know what the graph of sin(x) looks like. If we change the expression to 4 * sin(x), then the graph becomes "transformed". Instead of a wave between y = -1 and y = 1, the transformed graph has a sine wave between y = -4 and y = 4.

By altering the number in front of sin(x), we can transform the graph's wave to be as short or as tall as we like.

(1/4) * sin(x) will make the amplitude of the graph smaller.

100 * sin(x) will make the amplitude of the graph much larger.

There are many different types of transformations.

-sin(x) transforms the graph of sin(x) by reflecting it across the x-axis.

sin(x + Pi/2) transforms the graph of sin(x) by shifting it Pi/2 units to the LEFT.

sin(x - 10) transforms the graph of sin(x) by shifting it 10 units to the RIGHT

sin(x) + 5 transforms the graph of sin(x) by shifting the entire graph UP by 5 units.

sin(x) - 500 transforms the graph of sin(x) by shifting the entire graph DOWN by 500 units.

sin(3x) transforms the graph of sin(x) by compressing it by a factor of 3; in other words, you can fit three periods of the graph of sin(3x) into the same space as one period of the graph of sin(x).

reg said:
... where i should start?

If you understand the various transformations (i.e., how changing the values of a, b, c, and d affect the amplitude, horizontal shifting, vertical shifting, reflection [if any], and compression or stretching of the graph of h), then I would start by graphing your data. Then determine the values of a, b, c, and d needed to get the graph of h to roughly match the graph of your data.

If you do not understand what happens to the graph of h when you change the value of a, b, c, or d, then I would start by reviewing that material. If you have a graphing calculator, then use it to plot families of h as you review.

For example, if you're reviewing how the value of c shifts the graph of h horizontally, then plot the following expressions for h:

cos(t + 0)
cos(t + 1)
cos(t + 2)
cos(t + 3)

(in this example, a=1, b=1, and d=0).

Try changing the value of a, and see what happens to the graph of h.

-2 * cos(t)
-1 * cos(t)
cos(t)
2 * cos(t)

(here, the values are b=1, c=0, and d=0).

If you still do not have any idea on how to proceed to make the graph of h match the graph of your data, then please let us know. It's very helpful to us if you provide us with your thoughts on why you're stuck.

Cheers,

~ Mark :)
 
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