What I have got so far is:
\(\displaystyle \frac{dy}{dx} = tg θ = \frac{-y}{\sqrt{16-y^2}} \)
But now I'm stuck, since I don't know how to integrate that
What I have got so far is:
\(\displaystyle \frac{dy}{dx} = tg θ = \frac{-y}{\sqrt{16-y^2}} \)
But now I'm stuck, since I don't know how to integrate that
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