Tough nut but not calculus

psoft

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Jan 21, 2006
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9 0s are placed from 0th cell to 8th cell of an array; 6 1s are placed from 10th cell to end of the array. On the whole, there are 16 cells, so that just one cell remains unoccupied. 0s only move rightward; 1s move leftward. Every move is either a move to the next empty cell or a jump over one cell which has different value. In any case, no two values are allowed in the same square. The goal is to move 1s into 6 leftmost positions and the 0s into 9 rightmost positions. How many minimum moves are needed to achieve this?
Got the grey cells..............
Can anyone break this tough nut????????????
 
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