mmm4444bot
Super Moderator
- Joined
- Oct 6, 2005
- Messages
- 10,962
Here's a typing tip, for your consideration. ?
When posting multiple, consecutive lines of LaTex, you only need to invoke LaTeX once. That is, you may insert all lines within a single set of [͏tex] and [͏/tex] tags, IF you end each line with \\
For double-spacing, end a blank line with \;\\
Here's an example. Both of the following yield the same output.
[͏tex]x^2 + (y - x^{2/3})^2 = 5\\
\;\\
(y - x^{2/3})^2 = 5 - x^2\\
\;\\
\sqrt{(y - x^{2/3})^2} = \sqrt{5 - x^2}\\
\;\\
y - x^{2/3} = \pm\sqrt{5 - x^2}\\
\;\\
y = \pm\sqrt{5 - x^2} + x^{2/3}[͏/tex]
[͏tex]x^2 + (y - x^{2/3})^2 = 5[͏/tex]
[͏tex](y - x^{2/3})^2 = 5 - x^2[͏/tex]
[͏tex]\sqrt{(y - x^{2/3})^2} = \sqrt{5 - x^2}[͏/tex]
[͏tex]y - x^{2/3} = \pm\sqrt{5 - x^2}[͏/tex]
[͏tex]y = \pm\sqrt{5 - x^2} + x^{2/3}[͏/tex]
When posting multiple, consecutive lines of LaTex, you only need to invoke LaTeX once. That is, you may insert all lines within a single set of [͏tex] and [͏/tex] tags, IF you end each line with \\
For double-spacing, end a blank line with \;\\
Here's an example. Both of the following yield the same output.
[͏tex]x^2 + (y - x^{2/3})^2 = 5\\
\;\\
(y - x^{2/3})^2 = 5 - x^2\\
\;\\
\sqrt{(y - x^{2/3})^2} = \sqrt{5 - x^2}\\
\;\\
y - x^{2/3} = \pm\sqrt{5 - x^2}\\
\;\\
y = \pm\sqrt{5 - x^2} + x^{2/3}[͏/tex]
[͏tex]x^2 + (y - x^{2/3})^2 = 5[͏/tex]
[͏tex](y - x^{2/3})^2 = 5 - x^2[͏/tex]
[͏tex]\sqrt{(y - x^{2/3})^2} = \sqrt{5 - x^2}[͏/tex]
[͏tex]y - x^{2/3} = \pm\sqrt{5 - x^2}[͏/tex]
[͏tex]y = \pm\sqrt{5 - x^2} + x^{2/3}[͏/tex]