Time loss problem

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Corsair_cavalier

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Sep 25, 2005
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A clock loses x minutes every y hours. At the end of a week, how many hours would have been lost?

The answer can of course be easily found by substituting in some values for x and y (such as it loses 60 minutes every 24 hours).By doing this you can get (14x)/(5y). However, I am stubborn and would like to think it can be done algebraically without having to substitute any numbers in or anything. If this can be done then how? If not, why?
 
Corsair_cavalier said:
A clock loses x minutes every y hours. At the end of a week, how many hours would have been lost?
The answer can of course be easily found by substituting in some values for x and y (such as it loses 60 minutes every 24 hours).By doing this you can get (14x)/(5y). However, I am stubborn and would like to think it can be done algebraically without having to substitute any numbers in or anything. If this can be done then how? If not, why?
Click to expand...

hours in 1 week = 24 * 7 = 168

minutes lost in a week = x(168 / y)

tick tock ?
 
Don't feel bad; I went "baaaa....." a quite few times myself :lol:
 
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