Three impedances are connected in parallel

[momo12345]

I need some help guys on the following question.

Three impedances are connected in parallel.
?1=2?+3
?2=2−?
?3=5?
Find the equivalent admittance ? where
?=?1+?2+?3

and express it in a rectangular and polar form.

I've worked it down (and correct me if i'm wrong)

Z1 (2j-3/-5) + Z2(2+j/5) - Z3 (5j/-25) by multiplying the numerator and denominator times the conjugate of the denominator.

Now i'm lost on where to go from here.

 

[Deleted member 4993]

I need some help guys on the following question.

Three impedances are connected in parallel.
?1=2?+3
?2=2−?
?3=5?
Find the equivalent admittance ? where
?=?1+?2+?3

and express it in a rectangular and polar form.

I've worked it down (and correct me if i'm wrong)

Z1 (2j-3/-5) + Z2(2+j/5) - Z3 (5j/-25) by multiplying the numerator and denominator times the conjugate of the denominator.

Now i'm lost on where to go from here.

You say:

I've worked it down....

Z1 (2j-3/-5) + Z2(2+j/5) - Z3 (5j/-25)......... what does that "equal" to? I cannot follow your logic!!

Please show us first:

Y = Z1 + Z2 + Z3................................... what do you get here

Then show us (step by step) your continued effort.