find the x intercept: f(x) = -2/49x^2 + 10/7x
S shefflebat New member Joined Oct 15, 2005 Messages 3 Nov 15, 2005 #1 find the x intercept: f(x) = -2/49x^2 + 10/7x
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Nov 15, 2005 #2 Hello, shefflebat! Do you know HOW to find an x-intercept? Find the x intercept: .f(x) = −249x2 + 107x\displaystyle f(x)\;=\;-\frac{2}{49}x^2\,+\,\frac{10}{7}xf(x)=−492x2+710x Click to expand... Set the function equal to 0 and solve for x.\displaystyle x.x. We have: .-249x2 + 107x = 0\displaystyle \frac{2}{49}x^2\,+\,\frac{10}{7}x\;=\;0492x2+710x=0 Multiply through by -49: 2x2 − 70x = 0\displaystyle 49:\;\;2x^2\,-\,70x\;=\;049:2x2−70x=0 Factor: .2x(x − 35) = 0\displaystyle 2x(x\,-\,35)\;=\;02x(x−35)=0 Therefore: .x = 0, 35\displaystyle x\,=\,0,\,35x=0,35
Hello, shefflebat! Do you know HOW to find an x-intercept? Find the x intercept: .f(x) = −249x2 + 107x\displaystyle f(x)\;=\;-\frac{2}{49}x^2\,+\,\frac{10}{7}xf(x)=−492x2+710x Click to expand... Set the function equal to 0 and solve for x.\displaystyle x.x. We have: .-249x2 + 107x = 0\displaystyle \frac{2}{49}x^2\,+\,\frac{10}{7}x\;=\;0492x2+710x=0 Multiply through by -49: 2x2 − 70x = 0\displaystyle 49:\;\;2x^2\,-\,70x\;=\;049:2x2−70x=0 Factor: .2x(x − 35) = 0\displaystyle 2x(x\,-\,35)\;=\;02x(x−35)=0 Therefore: .x = 0, 35\displaystyle x\,=\,0,\,35x=0,35
