find the x intercept: f(x) = -2/49x^2 + 10/7x
S shefflebat New member Joined Oct 15, 2005 Messages 3 Nov 15, 2005 #1 find the x intercept: f(x) = -2/49x^2 + 10/7x
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Nov 15, 2005 #2 Hello, shefflebat! Do you know HOW to find an x-intercept? Find the x intercept: .\(\displaystyle f(x)\;=\;-\frac{2}{49}x^2\,+\,\frac{10}{7}x\) Click to expand... Set the function equal to 0 and solve for \(\displaystyle x.\) We have: .-\(\displaystyle \frac{2}{49}x^2\,+\,\frac{10}{7}x\;=\;0\) Multiply through by -\(\displaystyle 49:\;\;2x^2\,-\,70x\;=\;0\) Factor: .\(\displaystyle 2x(x\,-\,35)\;=\;0\) Therefore: .\(\displaystyle x\,=\,0,\,35\)
Hello, shefflebat! Do you know HOW to find an x-intercept? Find the x intercept: .\(\displaystyle f(x)\;=\;-\frac{2}{49}x^2\,+\,\frac{10}{7}x\) Click to expand... Set the function equal to 0 and solve for \(\displaystyle x.\) We have: .-\(\displaystyle \frac{2}{49}x^2\,+\,\frac{10}{7}x\;=\;0\) Multiply through by -\(\displaystyle 49:\;\;2x^2\,-\,70x\;=\;0\) Factor: .\(\displaystyle 2x(x\,-\,35)\;=\;0\) Therefore: .\(\displaystyle x\,=\,0,\,35\)
