This is my work for 'y = k*sqrt(x) / z^2'

[Gus]

This is what I got.
y = k*sqrt(x)/z^2
k = y*z^2/sqrt(x)
k = 5.754*7.95^2/sqrt(1.12)
k = 343.6331900

y = 343.6331900*sqrt(4.18)/4.88^2
y = 29.50146620

Did I do this right?

Thanks

Angus

 

[Gus]

this is the question

If y varies directly as the square root of x and inversely as the square of z and y=5.754 when x=1.12 and z=7.95, then find y when x=4.18 and z =4.88.
y=?

 

[Deleted member 4993]

Re: This is my work.

This is what I got.
y = k*sqrt(x)/z^2
k = y*z^2/sqrt(x)
k = 5.754*7.95^2/sqrt(1.12)
k = 343.6331900

y = 343.6331900*sqrt(4.18)/4.88^2

y = 29.50146620........Looks good to me

Did I do this right?

Thanks

Angus