Thermodynamics help please and thank you.

[Andrew_Risk]

Hello, first time poster, life long user of math, My name is Andrew Risk, I am going to school for Power Engineering, 4th class, Need a new career, the life of a grunt has lost its appeal. That's my back round, here's the question: 26.000kg of copper at 33.000 degrees Celsius receives 460.000 KJ of heat. Calculate the final temperature of the metal. So would the formula be Q = mCp(T1-T2), then Q/mCp = (d)T
Add (d)T to T1 or would it be The specific heat of copper = 0.386 J / gram K = 386 J / kg K

Thus 460,000 = 26 (386) dT ==> dT = 460/(26(386)) = 21.81, So the final temperature = 33 + 21.81 = 54.81, Thanks for any help, I cant get out of bold font, and pressing enter doesn't break the paragraphs, is it just me? Again, I am wondering if I am wrong? as I have no idea how I could check. thanks. Andrew

 

[Deleted member 4993]

Hello, first time poster, life long user of math, My name is Andrew Risk, I am going to school for Power Engineering, 4th class, Need a new career, the life of a grunt has lost its appeal. That's my back round, here's the question: 26.000kg of copper at 33.000 degrees Celsius receives 460.000 KJ of heat. Calculate the final temperature of the metal. So would the formula be Q = mCp(T₁-T₂), then Q/(mC_p) = dT
Add (d)T to T1 or would it be The specific heat of copper = 0.386 J / gram K = 386 J / kg K

Thus 460,000 = 26 (386) dT ==> dT = 460/(26(386)) = 21.81, So the final temperature = 33 + 21.81 = 54.81, Thanks for any help, I cant get out of bold font, and pressing enter doesn't break the paragraphs, is it just me? Again, I am wondering if I am wrong? as I have no idea how I could check. thanks. Andrew

Looks good to me.