Re: perimeter problems
Alright, so you don't have any given values for the length and width of the triangle, so let's assign them variables: length will be L, and width will be W.
You know the relationship between length and width. The width is 25% of the length, so say the length was 100, then the width would be 25, correct? But since you are using variables for the actual values, the length would be L and the width would be 25% of L or 1/4 of L so you could say the width is equal to:
(25%)*L <<<<<<<< the word "percent" actually means "per one hundred" or " /100" so: (25%)*L equals
(25/100)*L
or
(1/4)*L
or just
L/4
so now you know that the length is L and the width is L/4.
L = L
W = L/4
Using these you can make an equation for the perimeter of the rectangle. Perimeter is the sum of the sides of the rectangle, so:
L + L + (W) + (W)
But instead of W, substitute in what you found W to be in terms of L
Hope that helps!
