the transformation that gives a straight line graph

[change_for_better]

Can you clarify this question for me:

Consider the relation y=25e^3x ,the transformation that gives a straight line graph is:

1)lny is plotted against ln(3x)
2)lny is plotted against lnx
3)y is plotted against x
4)y is plotted against lnx
5)lny is plotted against x

 

[Deleted member 4993]

Can you clarify this question for me:

Consider the relation y=25e^3x ,the transformation that gives a straight line graph is:

1)lny is plotted against ln(3x)
2)lny is plotted against lnx
3)y is plotted against x
4)y is plotted against lnx
5)lny is plotted against x

They are asking you write the given (exponential) equation in linear form.

For these types of (exponential) equations, that is generally accomplished by taking "natural log" of both the expressions (on two sides of "=" sign).

 

[mmm4444bot]

We can choose values for x, and then find the corresponding values of y, to make a table of (x,y) values.

Plotting the values from this table would produce an exponential curve, right?

Now, let's look at multiple-choice (2), for example. If we now take the natural logarithm of both the x and y values in the table, then we would form a new table with (ln[x],ln[y]) values.

The question is asking whether or not the graph of these new points would be linear. (Same goes for the other multiple choices.)

 

[change_for_better]

Thank you very much mmm4444bot and Subhotosh Khan


I understand now the question.

I must take ln to both sides of the equation ,then the answer will be lny=ln25+3x

so I think the correct answer will be 5)lny is plotted against x

 

[Deleted member 4993]

Thank you very much mmm4444bot and Subhotosh Khan


I understand now the question.

I must take ln to both sides of the equation ,then the answer will be lny=ln25+3x

so I think the correct answer will be 5)lny is plotted against x<<<< Correct