The three Gibbons brothers are all 3 years apart in age......

[eddy2017]

This seems like a real simple age problem. it is giving me a headache.
How can an equation be set up for this?
Appreciate like always any hint/

The three Gibbons brothers are all 3 years apart in age. The total of their ages equals 33 years. What is the age of the oldest brother?

 

[pka]

This seems like a real simple age problem. it is giving me a headache.
How can an equation be set up for this?
Appreciate like always any hint/

The three Gibbons brothers are all 3 years apart in age. The total of their ages equals 33 years. What is the age of the oldest brother?

Try [imath]3(Y+3)=33[/imath] where [imath]Y[/imath] is the age of the youngest.

 

[eddy2017]

Try [imath]3(Y+3)=33[/imath] where [imath]Y[/imath] is the age of the youngest.

Thanks, pka. I'll report back

 

[eddy2017]

Let's solve your equation step-by-step.
3(y+3)=33
Simplifyin' both sides of the equation.
(3)(y)+(3)(3)=33(Distribute)
3y+9=33
Subtractin' 9 from both sides.
3y+9−9=33−9
3y=24
y=8
the age of the youngest is 8 yrs.
what is the age of the oldest brother.
well, the problem says they are3 yrs apart from one another,so

youngest= 8 yrs
middle=11 yrs
oldest= 14 yrs

 

[eddy2017]

Try [imath]3(Y+3)=33[/imath] where [imath]Y[/imath] is the age of the youngest.

A simple stroke of wit!

 

[eddy2017]

Checking
[math]3(8+3)=33[/math][math]3*11=33[/math][math]33=33[/math]

 

[pka]

[imath]Y+Y+3+Y+6=33\\3Y+9=33\\Y+3=11\\Y=8\\8,~11,~\&~14[/imath]

 

[eddy2017]

[imath]Y+Y+3+Y+6=33\\3Y+9=33\\Y+3=11\\Y=8\\8,~11,~\&~14[/imath]

Awesome!
One thingy only
Where you get that 6?

 

[pka]

The oldest is six years older than the youngest.

 

[eddy2017]

The oldest is six years older than the youngest.

lol, wow, yes!. thanks, pka

 

[Deleted member 4993]

3 * Y_middle +(-3 + 0 +3) = 33 ... →...

Y_middle = 11 ...→...

Y_younger = 11 - 3 = 8 ...→...

Y_older = 11 + 3 = 14

check

8 + 11+14 = 33 ....... √

 

[eddy2017]

3 * Y_middle +(-3 + 0 +3) = 33 ... →...

Y_middle = 11 ...→...

Y_younger = 11 - 3 = 8 ...→...

Y_older = 11 + 3 = 14

check

8 + 11+14 = 33 ....... √

Wow what's this!. ?

Is there any other subject more interesting than Math? Rethorical question? NOOO

 

[BigBeachBanana]

Or let Y be the age of the youngest, M be the age of the middle, and O is the age of the oldest.
(1) O= M + 3
(2) M= Y + 3 => Y= M-3
(3) Y + M + O = 33
Substitute (1) and (2) into (3):
(M-3) + M + (M + 3) = 3M = 33 => M =11, Y=8, O=14.

 

[eddy2017]

Or let Y be the age of the youngest, M be the age of the middle, and O is the age of the oldest.
(1) O= M + 3
(2) M= Y + 3 => Y= M-3
(3) Y + M + O = 33
Substitute (1) and (2) into (3):
(M-3) + M + (M + 3) = 3M = 33 => M =11, Y=8, O=14.

Hey, [math]BBB^2[/math], this is too much for this numb mind! LOL!
Kiddin', I loved that!