The Thread I'm going to use for my Intermediate/Advanced Algebra Questions!

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Centurion

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Instead of posting separate threads for individual questions that pop up, I am going to use this thread. I often have questions about some of the more basic algebraic functions since I am not sure about them. At any rate...

Now I have the fraction ((rad6)/4) - the fraction 1/1 (1, obviously). How do I do this? Can you subtract normal, whole numbers like 1 from a radical? I would guess not. Thanks for the help!
 
Centurion said:
Instead of posting separate threads for individual questions that pop up, I am going to use this thread. I often have questions about some of the more basic algebraic functions since I am not sure about them. At any rate...

Now I have the fraction ((rad6)/4) - the fraction 1/1 (1, obviously). How do I do this? Can you subtract normal, whole numbers like 1 from a radical? I would guess not. Thanks for the help!
Click to expand...

No do not do that .....

Use one thread for one problem. Most of the time, if I have answered a post to my satisfaction - I do not go beck there. Most of the tutors over here also follow similar habit. So if you want prompt answer to your "new" problem - you had better use a new thread.
 
Centurion said:
Instead of posting separate threads for individual questions that pop up, I am going to use this thread. I often have questions about some of the more basic algebraic functions since I am not sure about them. At any rate...

Now I have the fraction ((rad6)/4) - the fraction 1/1 (1, obviously). How do I do this? Can you subtract normal, whole numbers like 1 from a radical? I would guess not. Thanks for the help!
Click to expand...

Yes you can .... some times that type of operation would be necessary in view of the total problem.

for example:

√6/4 - 1 = (√3 - 2√2)/(2√2)

which could be used in some problems. :p:p
 
Another question...

Um. You said not to, but I figure someone might answer it and I can't make ANOTHER thread right now. That would be superfluous.

Okay.

((2rad3)/3) x ((rad3)/2)

How do you multiply 2rad3 by rad3?
 
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