the person who made parabolas isnt at the top of my list

G

Guest

Guest
I really need help....

given the parabola : y^2-6y-8x-7=0

find the equation in standard form, vertex, focus, and equation of directrix

i duno why i am stuck on this....it seems simple but everytime I try it the awnsers dont fit with the graph....

the standard form equation is....
(x-2)^2=4p(h-k)

and the vertex =(h,k)
 
How does your text define "standard" form? And does it give you a formula for finding the vertex, or does it want you to complete the square? What other formulas, if any, does it provide?

Thank you.

Eliz.
 
Set up your equation as \(\displaystyle y^{2}-6y=8x+7\)

Complete the square. You will then have it in the form Stapel gave you.

Vertex is V(h,k)

Focus is F(h+p,k)

Directrix is x=h-p
 
Is this the right awnser for the problem?

standard form of equation : (y-3)^2= 8(x+2)

vertex: (-2,3)
focus: (0,3)
equation of directrix: x=-4
 
Yes, it is. Very good. See, you can do it. Just a shove in the right direction. They're not that bad. Just take your time and be careful. With all those h's and k's and what not it's easy to get something backwards.
 
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