the operation mod, how it works with polynomial...

esoli

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Feb 8, 2012
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hi, anyone can explain to me how the operation mod works with this expansion? I know just b mod a=c if b=a*n+c!

the definition of right cyclic shift,
v(1)(x) = vn−1 + v0x + · · · + vn−2xn−1
= vn−1 + v0x + · · · + vn−2xn−1 + vn−1xn − vn−1xn
= xv(x) − vn−1(xn − 1)
= xv(x) mod (xn − 1)
 
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