The Circle that's a Square, Squarcle. S^2=PI(R)^2

[Genius]

Thanks

 

[skeeter]

Can't wait to see some of the responses to this post ...

 

[stapel]

So what would happen if S^2 is equal to PI(R)^2. We would have a circle with the same area as a square. This is supposed to be impossible because PI is irregular.

Um... You might want to try taking a little closer look at the actual statement of the classical problem.

"There is no way, with only a collapsible compass and an unmarked straightedge, in a finite number of steps, to geometrically construct a square having the same area as a given circle."

All you have done in your post is show that the square of a square root equals itself, and that (a/1)(b/a) = b for non-zero values of "a". I doubt you'll find anybody here who would argue these tautologies.... :shock:

Eliz.

 

[Denis]

Well Genius, you can always make a circle with a string;
then use 4 pins forcing that string to become a square... :roll: