I am guessing that P(A) stands for the power set, i.e., set of all subsets of A. I remember vaguely that there is a theorem that P(A) is always larger than A, which would mean that there is no biggest set.It a riddle:
Is it exist?
I have a hint: P(A)
I don't understand the hint.
Right. Thank you.I am guessing that P(A) stands for the power set, i.e., set of all subsets of A. I remember vaguely that there is a theorem that P(A) is always larger than A, which would mean that there is no biggest set.
This is a good statement to try to prove. All you need to do, though, is to prove that P(A) > A (and that, aside from the empty set there is no set such that P(A) = A.)Does P(P(A)) > P(A) always?
I'd argue that [imath]P(\empty) > \empty[/imath] since [imath]P(\empty)[/imath] has one element, which is the empty subset.aside from the empty set there is no set such that P(A) = A.
I remember less vaguely now: https://en.wikipedia.org/wiki/Cantor's_diagonal_argument#General_setsI remember vaguely that there is a theorem that P(A) is always larger than A, which would mean that there is no biggest set.