Thank you all, one more question for now

[thelazyman]

Really difficult one in my opinion.

Find the equation of the tangent to the curve defined by y=e^x that is perpendiculat to the line defined by 3X + y = 1

thanks

 

[stapel]

You've had many similar exercises explained and done for you. How far have you gotten on your own? You've taken the derivative, you've found the slope (perpendicular to the given line's slope) that you're looking for, and... then what?

Please reply with specifics. Thank you.

Eliz.

 

[thelazyman]

Is their anyone that can actually please be helpful, im just a grd 12 student trying to get a decent mark in Calculus. Just please help.

 

[stapel]

im just a grd 12 student trying to get a decent mark in Calculus. Just please help

So, as other tutors have suspected, your idea of "help" is "do it for me"...?

This exercise is very similar to others which have been done for you, and I listed the first two steps. What have you done? How far have you gotten?

I don't mean to be rude, but, as you were told earlier, we're not here to take your class for you. You need to show us what you've done and tell us where you're stuck. Finding the slope of a straight line from the line's equation, after all, is something you learned back in pre-calculus algebra. Can you at least show us what you've done on that?

Thank you.

Eliz.