tyri471 said:AN OBJECT IS THROWN UPWRAD FROM THE TOP OF A 160-FOOT BUILDING WITH AN INITIAL VELOCITY OF 48 FEET PER SECOND. tHE HEIGH( H) OF THE OBJECT AFTER (T) SECONDS IS GIVEN BY THE QUADRATIC EQUQTION H=-16T[sup:1bxen6od]2[/sup:1bxen6od]+48+160. WHEN WILL THE OBJECT HIT THE GROUND?