test

[tyri471]

AN OBJECT IS THROWN UPWRAD FROM THE TOP OF A 160-FOOT BUILDING WITH AN INITIAL VELOCITY OF 48 FEET PER SECOND. tHE HEIGH( H) OF THE OBJECT AFTER (T) SECONDS IS GIVEN BY THE QUADRATIC EQUQTION H=-16T2+48+160. WHEN WILL THE OBJECT HIT THE GROUND?

 

[Deleted member 4993]

AN OBJECT IS THROWN UPWRAD FROM THE TOP OF A 160-FOOT BUILDING WITH AN INITIAL VELOCITY OF 48 FEET PER SECOND. tHE HEIGH( H) OF THE OBJECT AFTER (T) SECONDS IS GIVEN BY THE QUADRATIC EQUQTION H=-16T[sup:1bxen6od]2[/sup:1bxen6od]+48+160. WHEN WILL THE OBJECT HIT THE GROUND?

Your equation is not correct - please read over your problem and post and fix it.

The object will hit the ground - when H = 0.

Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you.

 

[arthur ohlsten]

perhaps this will help
H=-16t^2+48t+160
factor out -16
H=-16[t^2-3-10]
factor
H=-16[t-5][t+2]

Arthur