anaantonia_
New member
- Joined
- Apr 22, 2022
- Messages
- 7
Ok, I have this.
for
r=∣[B]x[/B]∣[B]x[/B]=xe1+xe2
I need to proove:
∇.(rn[B]xx[/B])=(n+3)rn[B]x[/B]∇2rn=n2rn−2∇2(rn[B]x[/B])=n(n+2)rn−2[B]x[/B]
I tried to do it, but
The in first equation I got n+2
and in the second equation, i can't simplify to it.
Can you help me? *---*
for
r=∣[B]x[/B]∣[B]x[/B]=xe1+xe2
I need to proove:
∇.(rn[B]xx[/B])=(n+3)rn[B]x[/B]∇2rn=n2rn−2∇2(rn[B]x[/B])=n(n+2)rn−2[B]x[/B]
I tried to do it, but
The in first equation I got n+2
and in the second equation, i can't simplify to it.
Can you help me? *---*