Tensors: prooving ∇²*r^n

anaantonia_

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Apr 22, 2022
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Ok, I have this.

for
r=[B]x[/B]r = |[B]x[/B]|[B]x[/B]=xe1+xe2[B]x[/B] = x e_1 + x e_2
I need to proove:

.(rn[B]xx[/B])=(n+3)rn[B]x[/B]\nabla .(r^n [B]xx[/B])=(n+3)r^n [B]x[/B]2rn=n2rn2\nabla ^2 r^n = n^{2} r^{n-2}2(rn[B]x[/B])=n(n+2)rn2[B]x[/B]\nabla ^2 (r^n [B]x[/B])= n(n+2)r^{n-2}[B]x[/B]
I tried to do it, but
The in first equation I got n+2
and in the second equation, i can't simplify to it.
Can you help me? *---*
 
Ok, after correcting what I typed, I have this.

for
r=xr = |x|x=xe1+xe2x = x e_1 + x e_2
I need to proove:

.(rnxx)=(n+3)rnx\nabla .(r^n xx)=(n+3)r^n x2rn=n2rn2\nabla ^2 r^n = n^{2} r^{n-2}2(rnx)=n(n+2)rn2x\nabla ^2 (r^n x)= n(n+2)r^{n-2}x
I tried to do it, but
The in first equation I got n+2
and in the second equation, i can't simplify to it.
Can you help me? *---*
 
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