Taking First Derivative

[sparklemetink]

y = x + 100/x

This is what I did...

y^' = x + 100/x
=1 + (x(0)-100 (1))/x^2
=1 - 100/x^2

However, the answer in the back of the book says y' = (x^2 - 100)/x^2. I am not sure where I went wrong, or if I am wrong.

Thank you for your help.

 

[Deleted member 4993]

y = x + 100/x

This is what I did...

y^' = x + 100/x
=1 + (x(0)-100 (1))/x^2
=1 - 100/x^2

However, the answer in the back of the book says y' = (x^2 - 100)/x^2. I am not sure where I went wrong, or if I am wrong.

Thank you for your help.

You are correct.

(x^2 - 100)/x^2 = 1 - 100/x^2

 

[sparklemetink]

Thank you.